ACE YOUR ORACLE 1Z0-071 EXAM WITH NEWPASSLEADER

Ace Your Oracle 1z0-071 Exam with NewPassLeader

Ace Your Oracle 1z0-071 Exam with NewPassLeader

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Oracle Database SQL Sample Questions (Q270-Q275):

NEW QUESTION # 270
Which CREATE TABLE statement is valid?

  • A. Option C
  • B. Option D
  • C. Option B
  • D. Option A

Answer: B


NEW QUESTION # 271
You need to produce a report where each customer's credit limit has been incremented by $1000. In the output, the customer's last name should have the heading Nameand the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?

  • A. SELECT cust_last_name AS "Name", cust_credit_limit + 1000
    AS "New Credit Limit"
    FROM customers;
  • B. SELECT cust_last_name AS Name, cust_credit_limit + 1000
    AS New Credit Limit
    FROM customers;
  • C. SELECT INITCAP (cust_last_name) "Name", cust_credit_limit + 1000
    INITCAP ("NEW CREDIT LIMIT")
    FROM customers;
  • D. SELECT cust_last_name AS Name, cust_credit_limit + 1000
    "New Credit Limit"
    FROM customers;

Answer: A


NEW QUESTION # 272
View the Exhibit and examine the details of the PRODUCT_INFORMATION table. (Choose two.)

Evaluate this SQL statement:
SELECT TO_CHAR (list_price, '$9,999')
From product_information;
Which two statements are true regarding the output?

  • A. A row whose LIST_PRICE column contains value 1123.90 would be displayed as
    $ 1,123.
  • B. A row whose LIST_PRICE column contains value 11235.90 would be displayed as
    # ######.
  • C. A row whose LIST_PRICE column contains value 11235.90 would be displayed as
    $ 1,123.
  • D. A row whose LIST_PRICE column contains value 1123.90 would be displayed as
    $ 1,124.

Answer: B,D


NEW QUESTION # 273
See the Exhibit and examine the structure of the PROMOTIONS table:

Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:

What would be the outcome?

  • A. It generates an error because CASE cannot be used with group functions.
  • B. It generates an error because NULL cannot be specified as a return value.
  • C. It generates an error because multiple conditions cannot be specified for the WHEN clause.
  • D. It executes successfully and gives the required result.

Answer: D

Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END


NEW QUESTION # 274
You execute the following commands:

For which substitution variables are you prompted for the input?

  • A. None, because no input required
  • B. Only 'mgr_id'
  • C. Only 'hiredate'
  • D. Both the substitution variables 'hiredate' and 'mgr_id

Answer: D


NEW QUESTION # 275
......

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